The eccentricity of the hyperbola conjugate to the hyperbola $\frac{x^2}{4} - \frac{y^2}{12} = 1$ is

  • A
    $\frac{2}{\sqrt{3}}$
  • B
    $2$
  • C
    $\sqrt{3}$
  • D
    $\frac{4}{3}$

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